What is produced from the nuclear reaction 14N (d,n)?

In the nuclear reaction represented by 14N (d,n), a deuteron (d) interacts with a nitrogen-14 (14N) nucleus, resulting in the emission of a neutron (n) and the production of another nucleus. In this specific reaction, the 14N nucleus absorbs the deuteron, which consists of one proton and one neutron. The deuteron effectively contributes its neutron to the nitrogen nucleus, leading to the formation of an oxygen-15 (15O) nucleus.

The reason why 15O is formed can be understood through the following equation:

[^{14}{7}N + ^{2}{1}d \rightarrow ^{15}_{8}O + n]

In this equation, nitrogen-14 (having 7 protons and 7 neutrons) gains an extra proton and neutron from the deuteron, resulting in oxygen-15 (which has 8 protons and 7 neutrons) and the emitted neutron.

Therefore, the correct product of the nuclear reaction 14N (d,n) is indeed oxygen-15 represented by the choice that indicates 15O. Other isotopes listed do not correspond to this reaction outcome, as they would not match