What is the result of bombarding 20Ne with deuterons?

Prepare for the NMTCB PET Exam with flashcards and multiple choice questions, each offering hints and explanations. Excel in your certification test!

The reaction that occurs when bombarding 20Ne with deuterons (which are nuclei consisting of one proton and one neutron) is indeed represented by the nuclear reaction 20Ne (d, alpha) 18F-2.

In this context, the process involves the interaction of the deuteron with the carbon nucleus (20Ne). During this interaction, the deuteron can fuse with 20Ne, which leads to the emission of an alpha particle (which is essentially a helium nucleus comprised of two protons and two neutrons). The remaining nucleus after the reaction will then be 18F. The "−2" refers to the configuration or specifics of the resulting fluorine isotope in the context of the provided notation, but the key point is that the main products of this reaction are indeed 18F and the alpha particle.

This nuclear reaction signifies how light nuclei can interact and produce heavier isotopes while conserving nucleon number and charge according to the principles of nuclear physics. Thus, option A accurately describes the outcome of bombarding 20Ne with deuterons due to the specifics of nuclear fusion and decay processes involved in such reactions.

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